6. Trigonometric Ratios
SAT® Math: Geometry & Trigonometry · preview lesson
Trigonometry extends right-triangle relationships to find missing sides and angles using three primary ratios. For an acute angle theta in a right triangle:
SOH-CAH-TOA:
- sin(theta) = Opposite / Hypotenuse
- cos(theta) = Adjacent / Hypotenuse
- tan(theta) = Opposite / Adjacent
Finding a missing side: Identify which sides are involved and which trig ratio connects them, then solve.
Example: A ladder leans against a wall at a 60-degree angle. The ladder is 12 feet long. How high on the wall does it reach?
- The height is opposite to 60 degrees; the ladder (12) is the hypotenuse.
- sin(60) = height / 12, so height = 12 sin(60) = 12 (sqrt(3)/2) = 6*sqrt(3).
Key angle values to memorize:
- sin(30) = 1/2, cos(30) = sqrt(3)/2, tan(30) = 1/sqrt(3) = sqrt(3)/3
- sin(45) = cos(45) = sqrt(2)/2, tan(45) = 1
- sin(60) = sqrt(3)/2, cos(60) = 1/2, tan(60) = sqrt(3)
Complementary angle identity: sin(theta) = cos(90 - theta). On the SAT®, an equation like sin(x) = cos(32) means x + 32 = 90, so x = 58.
Radians vs. degrees: A full circle is 360 degrees or 2*pi radians.
- Conversion: degrees pi / 180 = radians; radians 180 / pi = degrees.
- Common conversions: 30 = pi/6, 45 = pi/4, 60 = pi/3, 90 = pi/2, 180 = pi.
Worked example: In right triangle ABC, angle C = 90 degrees, AB = 13, BC = 5. Find sin(A) and cos(A).
- BC is opposite angle A; AB is the hypotenuse.
- sin(A) = opposite/hypotenuse = 5/13.
- The third side AC = sqrt(13^2 - 5^2) = sqrt(169 - 25) = sqrt(144) = 12.
- cos(A) = adjacent/hypotenuse = 12/13.
- Pythagorean identity: sin^2(theta) + cos^2(theta) = 1 -- useful for substitution problems.
- Law of Sines / Cosines: Not typically required on the SAT®, but complementary identity questions appear frequently.
⚠️ Common mistake: Mixing up opposite and adjacent. Always label the triangle relative to the angle in question -- the opposite side never touches the angle; the adjacent side does (and is not the hypotenuse).
💡 Tip: If you forget a key trig value during the test, quickly sketch a 30-60-90 or 45-45-90 triangle using the special-right-triangle ratios from the formula sheet and read off the ratio directly.
No teacher notes have been added for this session.
No additional resources have been added for this session.
Lesson Discussion
Ask a question about this lesson. A teacher or admin can answer here.
Sign in to ask a question or save this lesson.
No questions yet for this lesson.